Programming-Idioms

Implementation
Haskell

Be concise.

Be useful.

All contributions dictatorially edited by webmasters to match personal tastes.

Please do not paste any copyright violating resource.

Please try to avoid dependencies to third-party libraries and frameworks.

Implementation edit is for fixing errors and enhancing with metadata.

Instead of changing the code of the snippet, consider creating another Haskell implementation.

Other implementations
import std.range;
list.chunks(2).each!writeln;
list.each_slice(2){|slice| p slice}
for x in zip(list[::2], list[1::2]):
    print(x)
for pair in list.chunks(2) {
    println!("({}, {})", pair[0], pair[1]);
}
import "fmt"
for i := 0; i+1 < len(list); i += 2 {
	fmt.Println(list[i], list[i+1])
}
foreach(array_chunk($list, 2) as $x) {
    echo $x[0], ' ', $x[1], PHP_EOL;
}
i := Low(L);
while (i < High(L)) do
begin
  writeln(L[i],', ', L[i+1]);
  Inc(i,2);
end;
for (pair <- list.grouped(2))
  println(s"(${pair(0)}, ${pair(1)})")
for (let index = 0; index < list.length; index = index + 2) {
  console.log(list[index], list[index + 1])
}
from itertools import tee
def pairwise(iterable):
    "s -> (s0,s1), (s1,s2), (s2, s3), ..."
    a, b = tee(iterable)
    next(b, None)
    return zip(a, b)

for a, b in pairwise(list):
    print(a, b)
use List::Util qw(pairs);
foreach (pairs @list) {
   print "@$_\n";
}
write (*,'(2I8,:," ")') list
Dim ItemList As New List(Of String)(New String() {"one", "one", "two", "two", "three", "three"})
For x = 0 To ItemList.Count - 1 Step 2
    Console.WriteLine(ItemList(x) & vbTab & ItemList(x + 1))
Next
using System.Collections.Generic;
for(int i = 0; i < list.Count; i += 2) {
  Console.WriteLine(string.Format("{0}, {1}", list[i], list[i + 1]));
}
(let print-pairs ((l list))
  (if (null? l)
      '()
      (begin
        (display (car l))
        (display " ")
        (display (cadr l))
        (newline)
        (print-pairs (cddr l)))))
#include <stdio.h>
for (unsigned i = 0; i < sizeof(list) / sizeof(list[0]); i += 2)
	printf("%d, %d\n", list[i], list[i + 1]);
pair :: [a] -> [(a, a)]
pair [] = []
pair (x:[]) = error "List had odd length"
pair (x:y:xs) = (x, y) : pair xs

mapM_ print (pair list)