Editing Idiom 42 : Continue outer loop

Idiom

# 42 Continue outer loop

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Lead paragraph

Print each item _v of list _a which in not contained in list _b.
For this, write an outer loop to iterate on _a and an inner loop to iterate on _b.

Implementation

Language

Pascal

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Last edited by

Imports

Code

  for v in a do
    begin
      for  w in b do
        if (v = w) then
          break;
      if (v = w) then
        Continue;
      writeln(v);
    end;

Documentation URL

Original attribution URL

Online demo

Edit summary

Username

Be concise.

Be useful.

All contributions dictatorially edited by webmasters to match personal tastes.

Please do not paste any copyright violating resource.

Please try to avoid dependencies to third-party libraries and frameworks.

Implementation edit is for fixing errors and enhancing with metadata.

Instead of changing the code of the snippet, consider creating another Pascal implementation.

Other implementations

mainloop:
	for _, v := range a {
		for _, w := range b {
			if v == w {
				continue mainloop
			}
		}
		fmt.Println(v)
	}

Demo

mainloop: for(int v:a){
	for(int w:b){
		if(v==w)
			continue mainloop;
	}
	System.out.println(v);
}

Demo

OUTER:
for my $v (@a) {
   for my $check (@b) {
      next OUTER if $v == $check;
   }
   print "$v not in the list\n";
}

OUTER:
for (var i in a) {
   for (var j in b) {
      if (a[i] === b[j]) {
         continue OUTER;
      }
   }
   console.log(a[i] + " not in the list");
}

'outer: for va in &a {
    for vb in &b {
        if va == vb {
            continue 'outer;
        }
    }
    println!("{}", va);
}

Demo

import std.stdio;

auto a = [1,2,3,4,5];
auto b = [3,5];

void main()
{
mainloop:
	foreach(v;  a){
		foreach(w; b){
			if(v == w) continue mainloop;
		}
		writeln(v);		 
	}
}

main()  {
  var a = [1, 2, 3];
  var b = [2, 3];

  outer: for (var v in a) {
    for (var w in b) {
      if (w == v) continue outer;
    }
    print(v);
  }
}

Demo

sequence_ [ print v | v <- a, [ u | u <- b, u == v] == [] ]

for v in a:
    try:
        for u in b:
            if v == u:
                raise Exception()
        print(v)
    except Exception:
        continue

a.each do |v|
  catch :matched do
    b.each do |u|
      throw :matched if v == u
    end
    puts v
  end  
end

$array_1 = [1,2,3,4,5];
$array_2 = [3,4];

foreach ($array_1 as $a) {
    foreach ($array_2 as $b) {
        if ($b == $a) {
            continue 2;
        }
    }
    echo $a
}

int *v = a;
while (v < a+N)
{
    int *w = b;
    while (w < b+M)
    {
        if (*v == *w)
            goto OUTER;
        
        ++w;
    }
    printf("%d\n", *v);
    
    OUTER: ++v;
}

#include <iostream>

auto a = {1,2,3,4,5};
auto b = {3,5};

for (auto va: a){
    for (auto vb: b){
        if (va==vb) goto OUTER;
    }
    std::cout << va << '\n';
    OUTER: continue;
}

  outer: do i=1,size(a)
     do j=1,size(b)
        if (a(i) == b(j)) cycle outer
     end do
     print *,a(i)
  end do outer

int[] alist = {1,2,3,4,5};
int[] blist = {3,4};
int gb = 0;
foreach (int a in alist)
{
  foreach (int b in blist)
  {
    gb = b;
    if (b == a)
      break;
  }
  if (gb == a)
    continue;
  System.Console.WriteLine(a);
}

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