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Idiom #41 Reverse a string

Create string t containing the same characters as string s, in reverse order.
Original string s must remain unaltered. Each character must be handled correctly regardless its number of bytes in memory.

Illustration
t = s.decode('utf8')[::-1].encode('utf8')
char[] charArray = s.ToCharArray();
Array.Reverse(charArray);
string t = new string(charArray);
import std.range, std.array;
auto t = s.retro.array;
var t = new String.fromCharCodes(s.runes.toList().reversed);
var t = s.split('').reversed.join();

1
t = String.reverse(s)
T = lists:reverse(S)
runes := []rune(s)
for i, j := 0, len(runes)-1; i < j; i, j = i+1, j-1 {
   runes[i], runes[j] = runes[j], runes[i]
}
t := string(runes)
t = reverse s :: String
-1
var t = s.split("").reverse().join("");
String t = new StringBuilder(s).reverse().toString();
function utf8.reverse(s)
	local r = ""
	for p,c in utf8.codes(s) do
		r = utf8.char(c)..r
	end
	return r
end

t = utf8.reverse(s)
for ($i=0;$i<mb_strlen($s);$i++) {
    $characters[] = mb_substr($s, $i, 1, 'UTF-8');
}

$characters = array_reverse($characters);
$t = implode($characters);
Function ReverseString(const AText: string): string;
var
    i,j:longint;
begin
  setlength(result,length(atext));
  i:=1; j:=length(atext);
  while (i<=j) do
    begin
      result[i]:=atext[j-i+1];
      inc(i);
    end;
end;
function reverse(const str: string): string;
var
  i, j: Integer;
begin
  j := length(str);
  setlength(reverse, j);
  for i := 1 to j do
    reverse[i] := str[j - i + 1];
end;
my $t = scalar reverse $s;
t = s.reverse
let t = s.chars().rev().collect::<String>();
s.reverse

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Idiom created by

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