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Programming-Idioms

# 286 Iterate over characters of a string
Print a line "Char i is c" for each character c of the string s, where i is the character index of c in s (not the byte index).

Make sure that multi-byte characters are properly handled, and count for a single character.
New implementation

Be concise.

Be useful.

All contributions dictatorially edited by webmasters to match personal tastes.

Please do not paste any copyright violating material.

Please try to avoid dependencies to third-party libraries and frameworks.

Other implementations 
(dorun (map-indexed (fn [i c] (println "Char" i "is" c)) s))
s.split('').asMap().forEach((i, c) => print('Char $i is $c'));
use iso_fortran_env
  integer, parameter :: ucs4  = selected_char_kind ('ISO_10646')
  character(kind=ucs4,  len=30) :: s
open (output_unit, encoding='UTF-8')

do i=1,len(s)
  print *,"Char ", i, " is ", s(i:i)
end do

i := 0
for _, c := range s {
	fmt.Printf("Char %d is %c\n", i, c)
	i++
}
forM_ (zip [0 ..] s) (\(i, c) -> putStrLn $ "Char " ++ show i ++ " is " ++ [c])
for (const [i, c] of [...s].entries()) {
	console.log(`Char ${i} is ${c}`);
}
import java.util.concurrent.atomic.AtomicInteger;
AtomicInteger i = new AtomicInteger(0);
s.chars().forEach(v -> {
  char c = (char)v;
  System.out.println("Char " + i.getAndIncrement() + " is " + c); 
});
for(int i=0; i<s.length(); i++) {
  char c = s.charAt(i);
  System.out.println("Char " + i + " is " + c); 
}
int i = 0;
for(char c : s.toCharArray()) {
	System.out.printf("Char %d is %c%n", i, c);
	i++;
}
s.forEachIndexed { i, c ->
  println("Char $i is $c")
}
lazutf8
for i := 1 to utf8length(s) do
  writeln(format('Char %d is %s',[i, utf8copy(s,i,1)]));
use v5.10;
use utf8;
binmode STDOUT, ":utf8"; 

while ($s =~ /(\X)/g) {
    say 'Char ' . pos($s) . ' is ' . $1;
}
for i, c in enumerate(s):
    print(f'Char {i} is {c}')

s.each_char.with_index{|c, i| puts "Char #{i} is #{c}" }
for (i, c) in s.chars().enumerate() {
    println!("Char {} is {}", i, c);
}

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