Creating implementation for idiom 46 : Extract beginning of string (prefix)

Idiom

# 46 Extract beginning of string (prefix)

Created by

Lead paragraph

Create string t consisting of the 5 first characters of string s.
Make sure that multibyte characters are properly handled.

New implementation

Language

Imports

Code

Documentation URL

Original attribution URL

Online runnable demo

Username

Be concise.

Be useful.

All contributions dictatorially edited by webmasters to match personal tastes.

Please do not paste any copyright violating material.

Please try to avoid dependencies to third-party libraries and frameworks.

Other implementations

T : String := S (1 .. 5);

(def t (apply str (take 5 s)))

IDENTIFICATION DIVISION.
PROGRAM-ID. prefix 5.
PROCEDURE DIVISION.
    MOVE s(1:5) TO t 	
STOP RUN.

auto t = s.substr(0, 5);

string t = s.Substring(0, 5);

string t = s[0..5];

var t = s.substring(0, 5);

t = String.slice(s, 0, 5)

[A, B, C, D, E | _] = S,
T = [A, B, C, D, E].

T = string:slice(S, 0, 5).

 character(len=5) :: t
 t = s(1:5)

t := string([]rune(s)[:5])

def t = s.take(5)

def t = s[0..<5]

import qualified Data.Text as T

t :: T.Text
t = T.take 5 s

t :: String
t = take 5 s

let t = s.substring(0,5);

String t = s.substring(0,5);

val t = s.take(5)

(setf *t* (subseq s 0 5))

t = s:sub(1,5)

@import Foundation;

NSString *t=[s substringToIndex:5];

$t = mb_substr($s, 0, 5, 'UTF-8');

_t := Copy(_s, 1, 5);

my $t = substr($s,0,5);

t = s[:5]

t = s[0, 5]

t = s.slice(0, 5)

t = s.slice(0...5)

let t = s.char_indices().nth(5).map_or(s, |(i, _)| &s[..i]);

let t = s.chars().take(5).collect::<String>();

val t = s.take(5)

s first: 5