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Programming-Idioms

Create string t consisting in the 5 last characters of string s.
Make sure that multibyte characters are properly handled.
New implementation

Be concise.

Be useful.

All contributions dictatorially edited by webmasters to match personal tastes.

Please do not paste any copyright violating material.

Please try to avoid dependencies to third-party libraries and frameworks.

Other implementations
(let [t (clojure.string/join (take-last 5 s))])
(def t 
  (when (string? s)
    (let [from (-> s (count) (- 5) (max 0))]
      (subs s from))))
IDENTIFICATION DIVISION.
PROGRAM-ID. suffix.
PROCEDURE DIVISION.
    MOVE FUNCTION LENGTH(s) TO len
    COMPUTE pos = (len - 5) + 1
    MOVE    s(pos:) TO t    	 	
STOP RUN.
var t = s.Substring(s.Length - 5);
string t = s[$-5..$];
var n = s.length;
var t = s.substring(n-5, n);
<<_ :: binary-5>> <> t = s
t = String.slice(s, -5, 5)
[T5, T4, T3, T2, T1 | _] = lists:reverse(S),
T = [T1, T2, T3, T4, T5].
character(len=5) :: t
t = s(len(s)-4:)
t := string([]rune(s)[len([]rune(s))-5:])
final t = s[-5..-1]
t = drop (length s - 5) s
var t = s.slice(-5);
String t = s;
if (s.length()>= 5)
	t = s.substring(s.length()-5);
val t = s.takeLast(5)
(setf *t* (subseq s (- (length s) 5)))
@import Foundation;
NSString *t=[s substringFromIndex:s.length-5];
$t = mb_substr($s, -5, null, 'UTF-8');
Function RightStr(const AText: AnsiString; const ACount: Integer): AnsiString;
var j,l:integer;
begin
  l:=length(atext);
  j:=ACount;
  if j>l then j:=l;
  Result:=Copy(AText,l-j+1,j);
end;
use utf8;

my $t = substr($s, -5);
t = s[-5:]
t = s[-5..-1]
t = s[-5..]
let last5ch = s.chars().count() - 5;
let t: String = s.chars().skip(last5ch).collect();
s last: 5
t = s.Substring(s.Length - 5)
t = Right(s, 5)