# Programming-Idioms

# 68
Create an object x to store n bits (n being potentially large).
New implementation

Be concise.

Be useful.

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Please do not paste any copyright violating material.

Please try to avoid dependencies to third-party libraries and frameworks.

Other implementations
``#include <bitset>``
``std::bitset<n> x;``
``#include <bitset>``
``std::bitset<n> bs;``
``#include <vector>``
``std::vector<bool> x(n, 0);``
``using System.Collections;``
``new BitArray(n);``
``import std.bitmanip;``
``````BitArray x;
x.length = n;``````
``import 'package:bit_array/bit_array.dart';``
``final x = FixedBitArray(n);``
``x := make([]bool, n)``
``import "math/big"``
``var x *big.Int = new(big.Int)``
``x := make([]uint64, (n+63)/64)``
``import Data.Bits``
``````x :: Integer
x = sum [bit i | i <- [1..n], wannaset i]
``````
``let x = new Buffer (Math.ceil (n / 8))``
``import java.util.BitSet;``
``BitSet x = new BitSet(n);``
``(let ((x (make-array n :element-type 'bit))))``
``\$x = new BitSet(\$n);``
``````procedure Task;
var
x: Set Of Byte;
begin
x:= [2,4,8,16,32,64,256];
end;``````
``uses classes;``
``````procedure task;
var
x: TBits;
n: integer;
begin
n := \$FFF;
x := TBits.Create(n);
end;``````
``vec(\$x, \$n, 1) = 0;``
``````from __future__ import division
import math``````
``x = bytearray(int(math.ceil(n / 8.0)))``
``x = 0``
``let mut x = vec![false; n];``