Idiom #165 Last element of list

Assign to variable x the last element of list items.

import std.range;

int[] items;
auto x = items.back();

int[42] items;
int x = items[$-1];

(def x (last items))

(def x (peek items))

#include<vector>

std::vector<int> items;
int last = items.back();

#include <iterator>

auto x = *std::crbegin(items);

var x = items[items.Count-1];

using System.Linq;

var x = items.LastOrDefault();

x = items.last;

x = List.last(items)

x = lists:last(items),

x = items(ubound(items,1))

x := items[len(items)-1]

foo :: [a] -> Maybe a
foo [] = Nothing
foo xs = Just $ last xs

x = foo items

x = last items

const x = items[items.length - 1];

int x = items[items.length - 1];

var x = items.last()

local x = items[#items]

@import Foundation;

x=items.lastObject;

$x = $items[array_key_last($items)];

$x = end($items);

x := items[high(items)];

my $x = $items[-1];

my $x = $items[$#items];

x = items[-1]

x = items.last

x = items.last

let x = items.last().unwrap();

let x = items[items.len()-1];

val x = items.takeRight(1)

Dim ItemList As New List(Of String)(New String() {"one", "two", "three"})
Console.WriteLine(ItemList.Last)

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